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20 May, 20:16

If f (x) = (x^2-2x-1) ^2/3, then f' (0) is?

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  1. 20 May, 22:01
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    F' (x) = (2/3 (x^2-2x-1) ^-1/3) * (2x-2) chain rule here

    f' (0) is equals to substitute x with 0. Which gives

    f' (0) = (2/3 (-1) ^-1/3) * (-2)

    Plug in the calculator, and your answer is ready
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