Assume that during meiosis I, none of the CC chromosomes disjoin at metaphase, but they separate into dyads (instead of monads) during meiosis II. Each resultant gamete participated in fertilization with a normal haploid gamete. What combinations will result?

Question: Consider a diploid cell that contains three pairs of chromosomes, designated AA, BB, and CC. Each pair contains a maternal and paternal member Assume that during meiosis I, none of the C chromosomes disjoin at metaphase, but they separate into dyads (instead of monads) during meiosis II. Each resultant gamete participated in fertilization with a normal haploid gamete. What are the possibilities for the number of C chromosomes present in the resulting gametes?

Answer:

Gametes may have either 1 or 3 C chromosomes.

Explanation:

Gametes are a creature's generative cells. They are also mentioned to as gender cells. Female gametes are named ova or egg cells, and male gametes are named sperm. Gametes are haploid cells, and respectively cell brings individual single replica of respectively chromosome. Meiosis is a kind of cell partition that diminishes the amount of chromosomes in the parental cell by partial and produces four gamete cells. This method is essential to produce egg and sperm cells for sexual reproduction. Trisomy 21 happens once the 21st pair of chromosomes fail to isolated, and one gamete does not accept a replica of chromosome 21, while the other accepts two copies. When that gamete fertilizes/is fertilized, the resulting zygote contains three copies of chromosome 21.