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15 April, 23:38

A 1475 kg car with a speed of 66.5 km/h brakes to a stop. How many cal of heat are generated by the brakes as a result?

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Answers (2)
  1. 16 April, 03:12
    0
    Let's start by stating that the work done here would be determined by taking into account the following:

    -External forces

    -Change in kinetic energy

    Work Energy theorem is fully going to guide the solution to this problem.

    Let's go now:

    Mass of car = 1475kg

    Velocity of car = 66.5km/h

    Velocity = 66.5km/h * 0.278

    V = 18.472 m/s

    Kinetic Energy (K. E) = 1/2 (mv^2)

    K. E = 0.5 * 1475 * 18.472^2

    K. E = 737.5 * 341.214

    K. E = 251645.90 kgm^2/s^2

    1kgm^2/s^2 = 1 Joule

    So therefore,

    K. E = 251645.90 Joules

    K. E = 60.144KCals
  2. 16 April, 03:20
    0
    Answer:22.180

    Explanation:divide the two together then use the first three number after the decimal.

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