Mutation at this locus changes one allele to the other (i. e. it does not create a new allele). If the rate of mutation from allele 1 to allele 2 is 0.00005 and the rate of mutation from allele 2 to allele 1 is 0.01, what is the equilibrium frequency of allele 2 (Give your answer to 5 decimal places) ?

Question

Biology

Landen Crawford

3 October, 08:42

Mutation at this locus changes one allele to the other (i. e. it does not create a new allele). If the rate of mutation from allele 1 to allele 2 is 0.00005 and the rate of mutation from allele 2 to allele 1 is 0.01, what is the equilibrium frequency of allele 2 (Give your answer to 5 decimal places) ?

+5

Answers (1)

Know the Answer?

Isiah Mckee · Answer 1

0.00498

Explanation:

The equilibrium frequency can be calculated by the formula as follows:

qe = u / (u + v)

Here, qe is equilibrium frequency, u = 0.00005 = the forward mutation rate and v is the backward mutation rate = 0.01.

qe = 0.00005 / (0.00005 + 0.01) =

qe = 0.00498.

Thus, the answer is 0.00498.