Suppose that in plants, smooth seeds (S) are dominant to wrinkle seeds (s) and tall plants (T) are dominant to short plants (t). A tall plant with smooth seeds was backcrossed to a parent that was short and wrinkle. What proportion of the progeny is expected to be heterozygous for tall and smooth?

Question

Biology

Yareli Weaver

12 August, 06:03

Suppose that in plants, smooth seeds (S) are dominant to wrinkle seeds (s) and tall plants (T) are dominant to short plants (t). A tall plant with smooth seeds was backcrossed to a parent that was short and wrinkle. What proportion of the progeny is expected to be heterozygous for tall and smooth?

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Answers (1)

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Jada · Answer 1

1/4

Explanation:

According to the given information, the dominant plant is back-crossed with a homozygous recessive parent. Therefore, the dominant plant is heterozygous for both genes.

The genotype of the tall plant with smooth seeds would be = TtSs

And the genotype of the dwarf parent with wrinkled seeds = ttss

A cross between TtSs x ttss gives heterozygous tall plants with smooth seeds (TtSs) in 1/4 ratio.