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27 September, 04:49

Predict the Earth Mass (ME) of an exoplanet with an Earth Radius measure of 3.2 RE.

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  1. 27 September, 08:43
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    The relationship is modeled by the equation y = 7.7079x - 7.

    Here, y is the dependent variable which is the Earth Mass, and x is the independent variable which is the Earth Radius.

    Solving for the Earth Mass if Earth Radius is 3.2 (x=3.2), we substitute 3.2 to x.

    7.7079 (3.2) - 7

    =7.7079 times 3.2 - 7

    =24.66528-7

    =17.66528

    7.7079 (3.2) - 7=17.66528
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