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15 June, 07:37

Dr. Patton is a professor of English. Recently she counted the number of misspelled words in a group of student essays. She noted the distribution of misspelled words per essay followed the normal distribution with a population standard deviation of 2.44 words per essay. For her 10 A. M. section of 40 students, the mean number of misspelled words was 6.05. Construct a 95% confidence interval for the mean number of misspelled words in the population of student essays. (Round your answers to 3 decimal places.)

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  1. 15 June, 10:08
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    (5.294, 6.806) Answer

    Explanation:

    SD = 2.44

    Mean = 6.05

    z for 95% confidence interval = 1.96

    n=40

    Confidence Interval:

    (Mean - (z*SD) / sqrt (n), Mean + (z*SD) / sqrt (n))

    = (6.05 - (1.96*2.44) / sqrt (40), 6.05 + (1.96*2.44) / sqrt (40)))

    = (5.294, 6.806) Answer
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