Ask Question
3 June, 23:36

A 14 kg cannon ball is fired from a cannon with muzzle speed of 1319 m/s at an angle of 19.1 ◦ with the horizontal. The acceleration of gravity is 9.8 m/s 2. Use conservation of mechanical energy to find the maximum height reached by first ball. Answer in units of m

+4
Answers (1)
  1. 4 June, 01:08
    0
    hf = 9494.338 m

    Explanation:

    m = 14 Kg

    vi = 1319 m/s

    hi = 0

    ∅ = 19.1º

    viy = vi*Sin ∅ = (1319 m/s) * Sin 19.1º = 431.6 m/s

    vfy = 0

    We can apply

    Ei = Ef

    Ki + Ui = Kf + Uf

    ⇒ 0.5*m*viy² + m*g*0 = 0.5*m*0² + m*g*hf

    ⇒ hf = (0.5*viy²) / (g)

    ⇒ hf = (0.5 * (431.6 m/s) ²) / (9.81 m/s²)

    ⇒ hf = 9494.338 m
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A 14 kg cannon ball is fired from a cannon with muzzle speed of 1319 m/s at an angle of 19.1 ◦ with the horizontal. The acceleration of ...” in 📙 Business if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers