Amanda goes to the toy store to buy 1 ball and 3 different board games. If the toy store is stocked with 3 types of balls and 6 types of board games, how many different selections of the 4 items can Amanda make?

E) 60

Explanation:

total possible combinations for the board games = N! / K! (N-K) !

N = total number of items K = size of the subgroup

6! / [3! x (6-3) ! ]

6! = 6 x 5 x 4 x 3 x 2 x 1 = 720

3! = 3 x 2 x 1 = 6

6! / [3! x (6-3) ! ] = 720 / (6 x 6) = 720 / 36 = 20

total possible combinations for the ball = 3! / 1!2! = 6 / 2 = 3

total combinations for both 1 ball and 3 games = 20 x 3 = 60