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10 August, 16:57

You have $19,000 to invest, part at 6% and the rest at 7%. If x is the amount invested at 6 %6% , write an algebraic expression that represents the total annual income from both investments. Simplify the expression.

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  1. 10 August, 20:08
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    total annual income = 1330 - 0.01x

    Explanation:

    given data

    invest = $19,000

    some part at = 6%

    remaining part = 7%

    x is amount invested at = 6 %

    solution

    we know x part invested = 6 %

    so ($19,000 - x) part invested = 7 %

    so we get here total annual income from both investment that is

    income = 6% x + (19000 - x) 7%

    so total annual income = 0.06x + (19000 - x) 0.07

    total annual income = 1330 - 0.01x
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