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4 April, 18:11

A catering service offers 10 appetizers, 11 main courses, and 3 desserts. A customer is to select 6 appetizers, 8 main courses, 2 and desserts for a banquet. In how many ways can this be done

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  1. 4 April, 19:37
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    13,860 possible combinations

    Explanation:

    If you have 10 appetizers, 11 main courses and 3 desserts from which to choose from, and you can only select 6 appetizers, 8 main courses and 2 desserts, you can choose this may combinations:

    = [8! / 6! (8 - 6) !] x [11! / 8! (11 - 8) !] x [3! / 2! (3 - 2) !]

    11! = 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 39,916,800 8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40,320 6! = 6 x 5 x 4 x 3 x 2 x 1 = 720 3! = 3 x 2 x 1 = 6 2! = 2 x 1 = 2

    = [40,320 / 720 (2) ] x [39,916,800 / 40,320 (6) x [6 / 2 (1) ]

    = (40,320 / 1,440) x (39,916,800 / 241,920) x 3

    = 28 x 165 x 3 = 13,860
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