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19 March, 23:33

Complex numbers are often used when dealing with alternating current (AC) circuits. In the equation $V = IZ$, $V$ is voltage, $I$ is current, and $Z$ is a value known as impedance. If $V = 1-i$ and $Z=1+3i$, find $I$. Express your answer as a complex number in the form $a+bi$, where $a$ and $b$ are real numbers

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  1. 20 March, 01:43
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    Answer: I=-1/5-2/5i

    Explanation: V=IZ

    1-i=I (1+3i)

    Make I subject

    I = (1-i) / (1+3i).

    multiply numerator and denominator by conjugate (1-3i).

    The denominator will become

    1-9*i^2=1+9=10.

    The numerator will be expanded to be 1-3i-i + (3i) ^2=1-4i-3=-2-4i.

    This is I = (-2-4i) / 10

    divide numerator and denominator by - 2. We have:

    I = - (1+2i) / 5

    I=-1/5-2/5i
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