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26 April, 07:29

322 l of hydrogen occupies volume of 197 l at stp. what was the initial pressure exerted on the hydrogen constant

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  1. 26 April, 09:03
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    The initial pressure exerted on the hydrogen constant is caculated using the Boyles law formula

    that is P1V1=P2V2

    P1 = ?

    V1 = 322 L

    V2 = 197 L

    P2 = at STP = 760 mm hg

    P1 is therefore = P2V2/V1

    = 760 mmhg x 197 L / 322 L = 464.97 mmhg
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