Determine the molar solubility of pbso4 in pure water. ksp (pbso4) = 1.82 * 10-8.

a. 1.82 * 10-8 m

b. 1.35 * 10-4 m

c. 9.1 * 10-9 m

d. 3.31 * 10-16 m

e. 4.48 * 10-4 m

When PbSO₄ is added it dissociates as follows

PbSO₄ - - > Pb²⁺ + SO₄²⁻

molar solubility is the number of moles of solute that can be dissolved in 1 L of solution

if molar solubility of PbSO₄ is X, then molar solubility of Pb²⁺ is X and SO₄²⁻ is X

the formula for ksp is as follows

ksp - solubility product constant

ksp = [Pb²⁺][SO₄²⁻]

ksp = X * X

ksp = X²

ksp = 1.82 x 10⁻⁸

X² = 1.82 x 10⁻⁸

X = 1.35 x 10⁻⁴ M

molar solubility of PbSO₄ is 1.35 x 10⁻⁴ M

answer is b.