A certain gas is present in a 11.0 l cylinder at 3.0 atm pressure. if the pressure is increased to 6.0 atm, the volume of the gas decreases to 5.5 l. find the two constants ki, the initial value of k, and kf, the final value of k, to verify whether the gas obeys boyle's law.

Boyle's law is a special kind of ideal gas equation that can only be applied if the temperature is constant. The derived formula is:

PV = k

which means that there is a constant value for each product of any pressure and volume.

For Ki,

Ki = Pi*Vi = (3 atm) (11 L) = 33 L·atm

For Kf,

Kf = Pf*Vf = (6 atm) (5.5 L) = 33 L·atm

Since Ki = Kf, then the gas obeys Boyle's Law.