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4 December, 15:06

If 60 ml of naoh solution neutralizes 40 ml of 0.50 m h2so4, the concentration of the naoh solution is most nearly:

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  1. 4 December, 19:04
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    The balanced chemical equation for this reaction is:

    2NaOH (aq) + H2SO4 (aq) → Na2SO4 (aq) + 2H2O (l)

    According to question, 60 ml of NaOH solution was used for neutralizing 40 ml of 0.50M H2SO4.

    The no. of moles of H2SO4 is calculated using the equation:

    mol solute = (molarity) (L soln)

    mol H2SO4 = 0.50 M x 0.040 L = 0.02 moles of H2SO4

    As per the equation, the number of moles of NaOH used is:

    0.02 moles of H2SO4 (2 mol NaOH) (1 mol H2SO4) = 0.04 moles of NaOH

    Therefore, using the given volume of NaOH, the concentration or molarity of NaOH can be calculated using the formula:

    Molarity = mol solute/L soln = 0.04 mol NaOH/0.06 L = 0.67 M

    Therefore, the concentration of NaOH is 0.67 M.
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