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Chemistry
Destinee Whitney
16 April, 09:39
What is [OH-] in a 0.0035 M HCl solution?
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Franco Werner
16 April, 11:13
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We are given with concentration of H⁺, Starting by convertiong this concentration into pH as follow,
pH = - log [H⁺]
pH = - log [0.0035] ∴ conc. of HCl
pH = 2.45
Also,
pH + pOH = 14
pOH = 14 - 2.45
pOH = 11.55
Changing pOH into [OH⁻]
[OH⁻] = 10⁻¹¹°⁵⁵ ∴ Taking Antilog
[OH⁻] = 2.81 * 10⁻¹²
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