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16 April, 09:39

What is [OH-] in a 0.0035 M HCl solution?

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  1. 16 April, 11:13
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    We are given with concentration of H⁺, Starting by convertiong this concentration into pH as follow,

    pH = - log [H⁺]

    pH = - log [0.0035] ∴ conc. of HCl

    pH = 2.45

    Also,

    pH + pOH = 14

    pOH = 14 - 2.45

    pOH = 11.55

    Changing pOH into [OH⁻]

    [OH⁻] = 10⁻¹¹°⁵⁵ ∴ Taking Antilog

    [OH⁻] = 2.81 * 10⁻¹²
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