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24 October, 12:44

A chemistry lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid solution with a 20% solution. find the number of gallons needed of each solution.

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  1. 24 October, 13:06
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    The question above can be answered by using the volume balance concept. Two equations can be established by total volume balance and the component (acid) volume balance.

    If we let x be the volume of the 12% acid solution, the volume of the 20% acid solution will have to be 100 - x.

    x + (100 - x) = 100

    Then, the acid mass balance will give us the equation,

    (x) (0.12) + (100 - x) (0.20) = (100) (0.18)

    Simplifying,

    0.12x + 20 - 0.20x = 18

    -0.08x = 20 - 18

    -0.08x = 2

    The value of x from the equation is 25.

    Hence, the volume of the 12% acid solution is 20 galloons and that of the 20% acid solution is 75 galloons.
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