Given the lattice energy of kcl = 699 kj/mol, the ionization energy of k = 419 kj/mol and the electron affinity of cl = - 349 kj/mol, calculate the δh o for the reaction: k (g) + cl (g) → kcl (s)

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Chemistry

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28 January, 02:08

Given the lattice energy of kcl = 699 kj/mol, the ionization energy of k = 419 kj/mol and the electron affinity of cl = - 349 kj/mol, calculate the δh o for the reaction: k (g) + cl (g) → kcl (s)

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Addisyn Swanson · Answer 1

K - - - > K⁺ = Ionization energy

Cl - - - > Cl⁻ = Electron affinity

delta H = Lattice energy + Ionization energy of K + Electron affinity of Cl

Lattice energy is taken as negative here

delta H = - 699 + 419 - 349 = - 629 KJ