A typical barometric pressure in redding, california, is about 750 mm hg. calculate this pressure in atm and kpa.

From the problem statement, this is a conversion problem. We are asked to convert from units of mmHg to units atm and units of kPa. To do this, we need a conversion factor which would relate the different units involved. We either multiply or divide this certain value to the original measurement depending on what is asked. From literature, we will find that 1 atm is equal to 760 mmHg and it is also equal to 101.325 kPa. We do as follows:

750 mmHg (1 atm / 760 mmHg) = 0.9868 atm

0.9869 atm (101.325 kPa / 1 atm) = 99.9918 kPa

Therefore, 750 mmHg is equal to 0.9869 atm and 99.9918 kPa.