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16 October, 03:54

A gas sample contains 4.00g of CH4 and 2.00g of He. What is the volume of the sample at STP?

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  1. 16 October, 04:46
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    As we know that 1 mole of any gas when acting perfectly / ideally occupies 22.4 L of volume.

    It means that in order to calculate volume occupied both by CH₄ and He, we must calculate their moles.

    Hence,

    Moles are given as,

    Moles = Mass / Mass

    Moles of CH₄;

    Mole-CH₄ = 4 g / 16 g. mol⁻¹

    Mole-CH₄ = 0.25 mol

    Moles of He;

    Mole-He = 2 g / 4 g. mol⁻¹

    Mole-He = 0.5 mol

    Now adding moles of both gases,

    = 0.25 + 0.5

    = 0.75 mol

    Therefore, when,

    1 mole of gas occupy = 22.4 L of Volume

    Then,

    0.75 mol will occupy = X L of Volume

    Solving for X,

    X = (0.75 mol * 22.4 L) : 1 mole

    X = 16.8 L
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