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6 November, 12:21

When calculating energy changes for substances other than water, how do we account for the differences in their abilities to absorb or release heat?

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  1. 6 November, 14:52
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    The water and pot (/) have a temperature increase of 100-25 degrees C that is 75 degrees ... the formula Q=mass * SH * change in temperature can be used for both the water and the steel pot. Hence for steel pot Q=510 j/kg/degC*.5kg*75Deg C=19125 joule ... For water SH=4187 j/kg/C. QW =.45*4187*75=141311 joule. total heat (neglecting changes and losses to get the water to 100 deg C is 160436 joule or 160.4 kjoule. Note this does not boil the water it only raises the temperature to 100 degrees C. to boil the water requires approximately a futher 1250 kJ
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