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21 June, 15:32

What is the empirical formula for a substance containing 37.5 grams of carbon, c, 12.5 grams of hydrogen, h, and 50.0 grams of oxygen, o?

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  1. 21 June, 18:53
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    CH4O First, look up the atomic weights of the involved elements Atomic weight carbon = 12.0107 Atomic weight hydrogen = 1.00794 Atomic weight oxygen = 15.999 Now determine the number of moles of each element you have moles carbon = 37.5 / 12.0107 = 3.1222 mol moles hydrogen = 12.5 / 1.00794 = 12.4015 moles oxygen = 50 / 15.999 = 3.1252 So we have the ratio 3.1222 : 12.4015 : 3.1252 We need to find a ratio of small integers that closely matches the above ratio. First, divide all values by 3.1222 (selected because it's the smallest), giving 1 : 3.972 : 1.001 All of the above values are close to integers, so the ratio is 1 : 4 : 1 This indicates that the empirical formula is CH4O
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