If a gas in a closed container is pressurized from 15.2 atmospheres to 19.2 atmospheres and its original temperature was 25.0oC, what would the final temperature of the gas be?

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Chemistry

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11 December, 19:37

If a gas in a closed container is pressurized from 15.2 atmospheres to 19.2 atmospheres and its original temperature was 25.0oC, what would the final temperature of the gas be?

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Dante Hickman · Answer 1

From the gay lussac law which the pressure of a given amount of a gas held at constant volume is directly proportional to temperature in kelvin.

that is p1/T1=P2/T2

p1=15.2 atm

P2=19.2 atm

T1=25+273=298k

T2=?

15.2/298=19.2/T2

5721.6=15.2 T2 divide both sides by 15.2

therefore T2=376.4k or 103.4 degrees celsius