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21 October, 08:34

Determine the molar solubility for al (oh) 3 in pure water. ksp for al (oh) 3 = 1.3 x 10-33.

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  1. 21 October, 12:20
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    When Al (OH) ₃ dissolves it dissociates as follows;

    Al (OH) ₃ - - - > Al³⁺ + 3OH⁻

    molar solubility is the number of moles that can be dissolved in 1 L of solution

    if the molar solubility of Al (OH) ₃ is x then molar solubility of Al³⁺ is x and OH⁻ is 3x

    then solubility product constant - ksp formula is as follows

    ksp = [Al³⁺][OH⁻]³

    ksp = (x) (3x) ³

    ksp = x * 9x³

    ksp = 9x⁴

    ksp = 1.3 x 10⁻³³

    9x⁴ = 1.3 x 10⁻³³

    x = 3.4 x 10⁻⁹ M

    molar solubility of Al (OH) ₃ is therefore 3.4 x 10⁻⁹ M
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