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5 April, 04:27

Copper has a density of 8.96 g/cm3. if a cylinder of copper weighing 48.85 g is dropped into a graduated cylinder containing 20.00 ml of water, what will be the new water level?

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  1. 5 April, 06:57
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    To solve for the new water level, let us first calculate for the volume of the copper cylinder. The formula we can use is:

    V = m / ρ

    where V is the volume, m is the mass of the copper and ρ is the density, therefore:

    V = 48.85 g / (8.96 g / cm^3)

    V = 5.45 cm^3

    since cm^3 = mL

    V = 5.45 mL

    The new water level will be the initial volume of the graduated cylinder plus the volume of the copper cylinder, therefore:

    new water level = 20 mL + 5.45 mL

    new water level = 25.45 mL
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