One gram of alum, KAl (SO4) 2.12H2O, contains 1.3 * 1021 Al atoms. How many oxygen atoms are contained in 1.0 g alum?

Question

Chemistry

Chris Gould

4 September, 00:50

One gram of alum, KAl (SO4) 2.12H2O, contains 1.3 * 1021 Al atoms. How many oxygen atoms are contained in 1.0 g alum?

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Steve Mcbride · Answer 1

From the chemical formula, 1 formula unit of KAl (SO4) 2.12H2O encompasses 1 atom of Al = 4 * 2 atoms of O in KAl (SO4) 2 + 12 atoms of O in 12H2O which is equal to 20 atoms of O.

So, if you have 1.3 * 10^21 Al atoms, you have 20 * 1.3 * 10^21 O atoms will now be equal to 2.6 * 10^22 atoms of O.