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4 July, 20:11

The mole fraction of iodine, i2, dissolved in dichloromethane, ch2cl2, is 0.115. what is the molal concentration, m, of iodine in this solution?

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  1. 4 July, 21:28
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    The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is X = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:

    0.115 mol I₂

    1 - 0.115 = 0.885 mol CH₂Cl₂

    We need moles of solute, which we have, and must convert our moles of solvent to kg:

    0.885 mol x 84.93 g/mol = 75.2 g CH₂Cl₂ x 1 kg/1000g = 0.0752 kg CH₂Cl₂

    We can now calculate the molality:

    m = 0.115 mol I₂/0.0752 kg CH₂Cl₂

    m = 1.53 mol I₂/kg CH₂Cl₂

    The molality of the iodine solution is 1.53.
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