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22 February, 14:17

2co3 + (aq) + 2cl - (aq) →2co2 + (aq) + cl2 (g). e∘=0.483 v what is the cell potential at 25 ∘c if the concentrations are [co3+] = 0.717 m, [co2+] = 0.363 m, and [cl-] = 0.152 m and the pressure of cl2 is pcl2 = 3.40 atm?

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  1. 22 February, 16:51
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    Look for Q. The equation you would use to find Q would be - [Co2+] ^2 [PCl2] / [Co3+] ^2 [Cl-]^2

    then plug in the the numbers you are given into the equation [0.363 M]^2 [3.40 atm] / [0.717 M] ^2 [0.152] ^2 0.4480 / 0.0119 = 37.7183

    Next you would want to determine the value of n = 2

    then you will want to plug in the values you have to the final equation E=E∘ - (0.0591 (n)) logQ

    E = 0.71 - (0.0591 (2)) * log 37.7

    E = 0.71 - 0.02955 * 1.58

    E = 0.71 - 0.0467

    E = 0.6633
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