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3 June, 22:26

A 226.4-l cylinder contains 65.5% he (g) and 34.5% kr (g) by mass at 27.0°c and 1.40 atm total pressure. what is the mass of he in this container?

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  1. 4 June, 01:16
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    First, we determine the number of moles of gas present using the ideal gas equation.

    PV = nRT

    n = PV / RT

    n = (1.4 * 226.4) / (0.082 * (27 + 273.15))

    n = 12.88

    Next, we use the given percentages to find the moles of helium present

    Moles of helium = 0.655 * 12.88

    Moles of helium = 8.44

    Next, we use the formula:

    Mass = moles * molar mass

    Mass of helium = 8.44 * 4

    Mass of helium = 33.76 grams
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