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12 May, 13:35

How many moles of pcl5 can be produced from 23.0 g of p4 (and excess cl2) ? express your answer to three significant figures and include the appropriate units?

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  1. 12 May, 14:33
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    Balance Chemical equation is,

    P₄ + 10 Cl₂ → 4 PCl₅

    According to Balance Equation,

    123.89 g (1 mole) of P₄ reacts to produce = 4 Moles of PCl₅

    Then,

    23 g of P₄ will react with excess Cl₂ to produce = X moles of PCl₅

    Solving for X,

    X = (4 mol * 23 g) : 123.89 g

    X = 0.742 g of PCl₅

    Result:

    When 23 g of P₄ is reacted with excess Cl₂, 0.742 g of PCl₅ is produced.
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