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11 February, 04:39

What volume is needed to store 0.80 moles of helium gas at 204.6 kpa and 300 k?

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  1. 11 February, 05:34
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    Answer is: 9,7 L is needed to store helium gas.

    n (He) = 0,80 mol.

    p (He) = 204,6 kPa.

    T = 300 K.

    R = 8,314 J/K·mol; universal gas constant.

    Use ideal law eqaution: p·V = n·R·T.

    V = n·R·T / p.

    V (He) = 0,80 mol · 8,314 J/K·mol · 300 K : 204,6 kPa.

    V (He) = 9,75 L.
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