What is the particle's position at t = 3.0s? express your answer to three significant figures and include the appropriate units?

The only given information is the time in 3 seconds. We are asked to find the position, or the distance traveled. The working equation to be used here is:

x = v₀t + 1/2 at²

where

x is the distance

v₀ is the initial velocity

a is the acceleration

In order to solve this, let's assume the object is free falling. So v₀ = 0 and a = 9.81 m/s².

x = 0 + 1/2 (9.81) (3) ²

x = 44.145 meters