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20 June, 06:42

Calculate the ph of a 0.005 m solution of potassium oxide k2o

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  1. 20 June, 07:42
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    First, we have to see how K2O behaves when it is dissolved in water:

    K2O + H20 = 2 KOH

    According to reaction K2O has base properties, so it forms a hydroxide in water.

    For the reaction next relation follows:

    c (KOH) : c (K2O) = 1 : 2

    So,

    c (KOH) = 2 x c (K2O) = 2 x 0.005 = 0.01 M = c (OH⁻)

    Now we can calculate pH:

    pOH = - log c (OH⁻) = - log 0.01 = 2

    pH = 14-2 = 12
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