Ask Question
1 November, 02:34

The volume of 0.05 M H2SO4 is needed to completely neutralise 15ml of 0.1 M NaOH solution is

+3
Answers (1)
  1. 1 November, 05:35
    0
    V (NaOH) = 15 mL = 0.015 L

    C (NaOH) = 0.1 mol/L

    C (H₂SO₄) = 0.05 mol/L

    2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O

    n (NaOH) = V (NaOH) C (NaOH) = 2n (H₂SO₄)

    n (H₂SO₄) = V (H₂SO₄) C (H₂SO₄)

    V (NaOH) C (NaOH) = 2V (H₂SO₄) C (H₂SO₄)

    V (H₂SO₄) = V (NaOH) C (NaOH) / {2C (H₂SO₄) }

    V (H₂SO₄) = 0.015*0.1/{2*0.05}=0.015 L = 15 mL
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The volume of 0.05 M H2SO4 is needed to completely neutralise 15ml of 0.1 M NaOH solution is ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers