What is the molarity of a solution of Cu2SO4 if 250.0 mL of solution contains 14.1 g of Cu2SO4?

Copper (I) compounds in aqueous solutions are unstable and disproportionate:

Cu₂SO₄ = Cu + CuSO₄

Necessary for dissolution of non-aqueous solvent.

M (Cu₂SO₄) = 223.16 g/mol

m (Cu₂SO₄) = 14.1 g

v=0.250 L

n (Cu₂SO₄) = m (Cu₂SO₄) / M (Cu₂SO₄)

c=n (Cu₂SO₄) / v=m (Cu₂SO₄) / (vM (Cu₂SO₄))

c=14.1 / (0.250*223.16) = 0.253 mol/L

0.253 M