Ask Question
14 June, 22:40

What is the empirical formula of the phosphorus selenide?

+4
Answers (1)
  1. 14 June, 23:47
    0
    atomic mass of phosphorous = 31g atomic mass of selenium = 79g 45.2/31 = 1.45 which is nearly 1.5 mol of P 131.6 - 45.2 = 86.4g 86.4/79 = 1.09 which is nearly 1 mol of Se So the empirical formula of the phosphorus selenide is: P3Se2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the empirical formula of the phosphorus selenide? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers