How much heat energy is required to boil 87.7 g of ammonia, NH3? The molar heat of vaporization of ammonia is 23.4 kJ/mol.

Question

Chemistry

Audrey

8 January, 03:16

How much heat energy is required to boil 87.7 g of ammonia, NH3? The molar heat of vaporization of ammonia is 23.4 kJ/mol.

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Phoenix Arellano · Answer 1

Energy released from changing the phase of a substance from the gas phase to liquid phase can be calculated by using the specific latent heat of vaporization. Calculation are as follows:

Energy = 87.7 g (1 mol / 17.04 g) x 23.4 kJ/mol

Energy = 120.4 kJ