Ask Question
22 January, 19:49

Give the percent yield when 28.16 g of co2 are formed from the reaction of 8.000 moles of c8h18 with 4.000 moles of o2. 2 c8h18 + 25 o2 → 16 co2 + 18 h2o

+4
Answers (1)
  1. 22 January, 21:52
    0
    equal moles of C8H18 and O2 are reacted to give equal no. of moles of CO2.

    mole ratio of C8H18 = (1/2) x 8 = 4 moles

    mole ratio of O2 = (1/25) x 4 = 0.16 moles

    so, limiting reagent is O2

    the no. of moles of CO2 formed = 16 x 0.16 = 2.56 moles

    weight of CO2 formed (theoretical weight) = 2.56 x 44 = 112.64

    Percentage yield = (practical yiel/theoretical yield) x 100 = (28.16/112.64) x100 = 25%
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Give the percent yield when 28.16 g of co2 are formed from the reaction of 8.000 moles of c8h18 with 4.000 moles of o2. 2 c8h18 + 25 o2 → ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers