Ammonia is often formed by reacting nitrogen and hydrogen gases. how many liters of ammonia gas can be formed from 22.7 l of hydrogen gas at 93.0°c and a pressure of 49.6 kpa?

Nitrogen + hydrogen = ammonia

N2 + 3 H2 - - - > 2 NH3

from ideal gas equation that is pv = nRT where p is pressure, v = volume, n = number of moles, R = gas constant and t = temperature

from information above in the question

P = 49.6 kpa

V=22.7 L

t = 93 + 273=366 K

R=8.314 l. Kpa / mol

n=?

from ideal gas equation n = Pv/RT

n = (49.6 x22.7) / (8.314 x 366) = 0.37 moles of nitrogen

by use of moles ratio between N2 to NH3 from equation above which is 3:2 therefore moles of NH3 = 0.37 x2/3 = 0.247 moles of Nh3

1mole of ideal gas = 22.4 L at stp

what about 0.247 moles

(0.247 x22.4) / 1 = 5.53 liters of ammonia