A 0.02877 g sample of gas occupies 10.0-ml at 289.0 k and 1.10 atm. upon further analysis, the compound is found to be 38.734% c and 61.266% f. what is the molecular formula of the compound? (order: c, x)

Question

Chemistry

Kaliyah Dudley

24 February, 12:12

A 0.02877 g sample of gas occupies 10.0-ml at 289.0 k and 1.10 atm. upon further analysis, the compound is found to be 38.734% c and 61.266% f. what is the molecular formula of the compound? (order: c, x)

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Delaney Huff · Answer 1

Assuming ideal gas, we calculate the number of moles.

PV = nRT

n = PV / RT

n = (1.10 atm) (10 x 10^-3L) / [ (0.08205746 L atm / mol K) (289 K) ]

n = 4.64 x 10^-4 mol

SO the molar mass is:

molar mass = 0.02877 grams / 4.64 x 10^-4 mol

molar mass = 62.02 g/mol

The only possible combination is:

C2F2

C = 12 * 2 = 24

F = 19 * 2 = 38

24 + 38 = 62 g/mol