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17 April, 19:22

For the reaction 2 s (s) + 3 o2 (g) → 2 so3 (g), how much so3 can be produced from 4 g o2 and excess s? 1. 0.25 mol so3 2. 0.13 mol so3 3. 0.06 mol so3 4. 0.08 mol so3 5. 0.17 mol so3

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  1. 17 April, 21:52
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    The balanced equation for the above reaction is as follows;

    2S + 3O₂ - - > 2SO₃

    Stoichiometry of O₂ to SO₃ is 3:2

    O₂ is the limiting reactant and S is provided in excess. since O₂ is the limiting reactant, the whole amount is consumed in the reaction and amount of product formed depends on amount of limiting reactant present.

    Number of O₂ moles reacted - 4 g / 32 g/mol = 0.125 mol

    3 mol of O₂ forms 2 mol of SO₃

    therefore when 0.125 mol of O₂ reacts number of SO₃ moles - 2/3 x 0.125 mol

    Number of SO₃ moles formed - 0.0833 mol

    Answer is 4) 0.08 mol
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