Determine the direction of electron flow and label the anode and the cathode. label each electrode as negative or positive. write a balanced equation for the overall reaction

At anode is where oxidation takes place, that is

Cr (s) →Cr3 + (aq) + 3e - this is the oxidation

At cathode is where reduction takes place,

Fe3 + (aq) + 3e-→Fe (s). This is the reduction

Cell reaction is

Cr (s) →Cr3 + (aq) + 3e - where E°=0.73V

Fe3 + (aq) + 3e-→Fe (s) where E° = - 0.036V

Cr (s) + Fe3 + (aq) →Cr3 (aq) + Fe (s) E°cell=0.69V

Cell reaction for Cr (s) + Fe3 + (aq) → Cr3 + (aq) + Fe (s) is

E°cell is 0.69V