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31 May, 03:34

Boron has only to naturally occurring isotopes. The mass of boron-10 is 10.01294 amu and the mass of bornon-11 is 11.00931 amu. Calculate the relative abundances of the two isotopes

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  1. 31 May, 06:00
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    X=percent as a fraction of boron 10

    y=percent as a fraction of boron 11

    The percentages as fractions add to equal one

    x+y=1

    x=1-y

    10.01294x+11.00931y=10.811

    substitute in the value of x from equation 1 in to equation 2

    10.01294 (1-y) + 11.00931y=10.811

    multiply out and solve for y

    10.01294-10.01294y+11.00931y=10.811

    0.99637y=0.79806

    y=0.800967512 = approx 80.1 % boron 11 isotope

    100%-80.1%=19.9% boron 10 isotope
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