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4 April, 20:48

How many excess electrons must you add to an object to give it a charge of - 6.50 μc?

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  1. 4 April, 21:16
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    Micro = 10^-6

    n = nano = 10^-9

    (a) - 2.5 micro coulombs = - 2.5 X 10^-6

    The charge on a electron is always - 1.60 X 10^-19.

    So, given charge divided by charge on electron gives you number of electrons.

    (-2.5X10^-6) / (-1.60X10^-19) = 1.5625 X 10^13 excess electrons.

    (b) - 2.5 nano coulombs = - 2.5 X 10^-9

    The charge on a electron is always - 1.60 X 10^-19.

    So, given charge divided by charge on electron gives you number of electrons.

    (-2.5X10^-9) / (-1.60X10^-19) = 1.5625 X 10^10 excess electrons.

    Round my answers to 3 significant figures if needed or to the appropriate form asked by the question.
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