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12 June, 06:30

An 80.0-gram sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its internal energy increased by 7845 J. What is the specific heat of the gas?

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  1. 12 June, 07:50
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    According to thermodynamics, internal energy is equal to the sum of work done and the heat energy.

    U = q + W

    7845 J = q + ( - 346 J)

    q = 8191 J

    Since, q = mC (T2-T1)

    8191 J =.080 kg (C) (225 - 25) K

    C = 511.94 J / kg K
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