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1 August, 19:51

Iodine is prepared both in the laboratory and commercially by adding cl2 (g) to an aqueous solution containing sodium iodide: how many grams of sodium iodide, nai, must be used to produce 48.7 g of iodine, i2?

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  1. 1 August, 22:14
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    The balanced equation for the reaction between NaI and Cl₂

    2NaI and Cl₂ - - > 2NaCl + I₂

    stoichiometry of NaI to I₂ is 2:1

    this means that when 2 mol of NaI reacts, it produces 1 mol of I₂

    Molar mass of I₂ is 254 g/mol

    Number of I₂ moles produced - 48.7 g / 254 g/mol = 0.192 mol

    for 1 mol of I₂ to be formed - 2 mol of NaI required

    Therefore to form 0.192 mol of I₂ - 2 x 0.192 = 0.384 mol of NaI

    Then mass of NaI required - 0.384 mol x 150 g/mol = 57.6 g
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