What mass of na2co3 is present in 0.650 l of a 0.505 m na2co3 solution?

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Chemistry

Midge

16 December, 03:41

What mass of na2co3 is present in 0.650 l of a 0.505 m na2co3 solution?

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Trevino · Answer 1

V=0.650 L

c=0.505 mol/L

M (Na₂CO₃) = 106.0 g/mol

the amount of substance of sodium carbonate is:

n (Na₂CO₃) = vc

the mass of sodium carbonate is:

m (Na₂CO₃) = n (Na₂CO₃) M (Na₂CO₃)

m (Na₂CO₃) = vcM (Na₂CO₃)

m (Na₂CO₃) = 0.650*0.505*106.0=34.7945 g