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6 October, 22:51

Now assume you measure out exactly 2.0 mL of aluminum chloride into a third test tube. How many moles of aluminum chloride are in the tube?

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  1. 7 October, 01:31
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    First, convert 2.0 mL of AlCl3 to grams using the density, which is 2.48g/mL. So 2.48g/mL * 2.0 mL = 4.96g. Then find the molar mass of aluminum chloride and divide 4.96 by this number, which is 133.34g. 4.96g * (1mol/133.34g) =.0372 mols AlCl3. Check for significant digits though.
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