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11 July, 04:30

A tumor is injected with 0.8 grams of iodine-125, which has a decay rate of 1.15% per day. to the nearest day, how long will it take for half of the iodine-125 to decay?

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  1. 11 July, 06:00
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    If the initial amount is 0.8 grams, half of this amount would be 0.4 grams. But first, let's construct an equation for the decay rate. That would be:

    Amount left = Initial amount * (1 - Decay Rate) * Time

    0.4 = 0.8 (1 - 0.0115) (t)

    Solving for t,

    t = 0.51 days

    Technically, it's just half day. But if we convert to the nearest day, the answer would be 1 day.
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